RCC Structures Design For initial estimate for a beam design, the width is assumed 1/25th of span 1/30th of span 1/15th of span 1/20th of span 1/25th of span 1/30th of span 1/15th of span 1/20th of span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 15 cm² 16 cm² 17 cm² 14 cm² 15 cm² 16 cm² 17 cm² 14 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For M 150 grade concrete (1 : 2 : 4) the moment of resistance factor is 5.8 0.87 7.5 8.5 5.8 0.87 7.5 8.5 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design [A + (m - 1)ASC] known as equivalent concrete area of R.C.C. is given by Load factor method Ultimate load method None of these Modular ratio method Load factor method Ultimate load method None of these Modular ratio method ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The weight of reinforced concrete, is generally taken as 2500 kg/m³ 2300 kg/m³ 2400 kg/m³ 2200 kg/m³ 2500 kg/m³ 2300 kg/m³ 2400 kg/m³ 2200 kg/m³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) ANSWER DOWNLOAD EXAMIANS APP
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