RCC Structures Design For initial estimate for a beam design, the width is assumed 1/20th of span 1/15th of span 1/25th of span 1/30th of span 1/20th of span 1/15th of span 1/25th of span 1/30th of span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Spacing of stirrups in a rectangular beam, is Increased at the ends Decreased towards the centre of the beam Increased at the centre of the beam Kept constant throughout the length Increased at the ends Decreased towards the centre of the beam Increased at the centre of the beam Kept constant throughout the length ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The effective span of a simply supported slab, is None of these Distance between the centers of the bearings Clear distance between the inner faces of the walls plus twice the thickness of the wall Clear span plus effective depth of the slab None of these Distance between the centers of the bearings Clear distance between the inner faces of the walls plus twice the thickness of the wall Clear span plus effective depth of the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design [A + (m - 1)ASC] known as equivalent concrete area of R.C.C. is given by Modular ratio method None of these Ultimate load method Load factor method Modular ratio method None of these Ultimate load method Load factor method ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 456, the reinforcement in a column should not be less than 0.8% and not more than 8% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.5% and not more than 5% of cross-sectional area 0.7% and not more than 7% of cross-sectional area 0.8% and not more than 8% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.5% and not more than 5% of cross-sectional area 0.7% and not more than 7% of cross-sectional area ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/3Sb l = dt/2Sb l = dt/Sb l = dt/4Sb l = dt/3Sb l = dt/2Sb l = dt/Sb l = dt/4Sb ANSWER DOWNLOAD EXAMIANS APP
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