RCC Structures Design A flat slab is supported On beams On columns On columns monolithically built with slab On beams and columns On beams On columns On columns monolithically built with slab On beams and columns ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Total pressure on the vertical face of a retaining wall of height h acts parallel to free surface and from the base at a distance of h/4 h/2 h/3 2h/3 h/4 h/2 h/3 2h/3 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is Kx (1 + x/l) + bw K/x (1 + x/d) + bw All listed here Kx (1 - x/l) + bw Kx (1 + x/l) + bw K/x (1 + x/d) + bw All listed here Kx (1 - x/l) + bw ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the tendon is placed at an eccentricity e below the centroidal axis of the longitudinal axis of a rectangular beam (sectional modulus Z and stressed load P in tendon) the stress at the extreme top edge Is decreased by Pe/Z Is increased by PZ/e Is increased by Pe/Z Remains unchanged Is decreased by Pe/Z Is increased by PZ/e Is increased by Pe/Z Remains unchanged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The system in which high tensile alloy steel bars (silica manganese steel) are used as pre-stressing tendons, is known as C.L. standard system Freyssinet system Lee-McCall system Magnel-Blaton system C.L. standard system Freyssinet system Lee-McCall system Magnel-Blaton system ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS