RCC Structures Design An R.C.C. column is treated as short column if its slenderness ratio is less than 50 56 40 30 50 56 40 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The spacing of transverse reinforcement of column is decided by the following consideration. The least lateral dimension of the column All listed here Forty-eight times the diameter of transverse reinforcement Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column The least lateral dimension of the column All listed here Forty-eight times the diameter of transverse reinforcement Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of different sizes, should not be less than One diameter of thicker bar None of these One diameter of thinner bar Twice the diameter of thinner bar One diameter of thicker bar None of these One diameter of thinner bar Twice the diameter of thinner bar ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is wh (1 - sin φ)/(1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) w (1 - cos φ)/h (1 + sin φ) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The modular ratio ‘m’ of a concrete whose permissible compressive stress is ‘C’, may be obtained from the equation. m = 700/3C m = 1400/3C m = 3500/3C m = 2800/3C m = 700/3C m = 1400/3C m = 3500/3C m = 2800/3C ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² ANSWER DOWNLOAD EXAMIANS APP
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