RCC Structures Design Spacing of stirrups in a rectangular beam, is Kept constant throughout the length Decreased towards the centre of the beam Increased at the centre of the beam Increased at the ends Kept constant throughout the length Decreased towards the centre of the beam Increased at the centre of the beam Increased at the ends ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the diameter of longitudinal bars of a square column is 16 mm, the diameter of lateral ties should not be less than 7 mm 4 mm 6 mm 5 mm 7 mm 4 mm 6 mm 5 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is wh (1 - tan φ)/(1 + tan φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - sin φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - sin φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The reinforced concrete beam which has width 25 cm, lever arm 40 cm, shear force 6t/cm², safe shear stress 5 kg/cm² and B.M. 24 mt, Is safe in shear Is unsafe in shear Needs redesigning Is over safe in shear Is safe in shear Is unsafe in shear Needs redesigning Is over safe in shear ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to the tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The maximum stress ‘f’ in the beam, subjected to a maximum bending moment ‘M’, is f = (P/A) + (M/6Z) f = (P/'+ (Z/M) f = (A/P) + (M/Z) f = (P/A) + (M/Z) f = (P/A) + (M/6Z) f = (P/'+ (Z/M) f = (A/P) + (M/Z) f = (P/A) + (M/Z) ANSWER DOWNLOAD EXAMIANS APP
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