RCC Structures Design Spacing of stirrups in a rectangular beam, is Increased at the centre of the beam Decreased towards the centre of the beam Increased at the ends Kept constant throughout the length Increased at the centre of the beam Decreased towards the centre of the beam Increased at the ends Kept constant throughout the length ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The toe projection of foundation slabs is taken As one third of the base Equal to heel slab As one sixth of overall height of the wall Below ground surface As one third of the base Equal to heel slab As one sixth of overall height of the wall Below ground surface ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of the same size should not be less than 2.5 diameters One diameter 3 diameters 3.5 diameters 2.5 diameters One diameter 3 diameters 3.5 diameters ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Though the effective depth of a T-beam is the distance between the top compression edge to the centre of the tensile reinforcement, for heavy loads, it is taken as 1/12th of the span 1/16th of the span 1/8th of the span 1/10th of the span 1/12th of the span 1/16th of the span 1/8th of the span 1/10th of the span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The effective width of a column strip of a flat slab, is Diameter of the column Half the width of the panel Radius of the column One-fourth the width of the panel Diameter of the column Half the width of the panel Radius of the column One-fourth the width of the panel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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