RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 16 m effective span is 10 kg/cm², the length of the beam having nominal reinforcement, is 8 cm 6 cm 10 cm 12 cm 8 cm 6 cm 10 cm 12 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If C is creep coefficient, f is original pre-stress in concrete, m is modular ratio, E is Young's modulus of steel and e is shrinkage strain, the combined effect of creep and shrinkage is: (C - 1) mf + eE (1 - C) mf + eE (1 - C) mf - eE (C - 1) mf - eE (C - 1) mf + eE (1 - C) mf + eE (1 - C) mf - eE (C - 1) mf - eE ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 1343, total shrinkage for a pre-tensioned beam, is 3.0 × 10⁻⁵ 3.0 × 10⁻³ 3.5 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻⁵ 3.0 × 10⁻³ 3.5 × 10⁻⁵ 3.0 × 10⁻² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Lapped splices in tensile reinforcement are generally not used for bars of size larger than 24 mm diameter 36 mm diameter 30 mm diameter 18 mm diameter 24 mm diameter 36 mm diameter 30 mm diameter 18 mm diameter ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by (π/4). (ft .d/fb) (π/4). (ft .d3/fb) ft .d/4fb π ft .d²/fb (π/4). (ft .d/fb) (π/4). (ft .d3/fb) ft .d/4fb π ft .d²/fb ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS