RCC Structures Design If ‘A’ is the sectional area of a pre-stressed rectangular beam provided with a tendon pre-stressed by a force ‘P’ through its centroidal longitudinal axis, the compressive stress in concrete, is P/2A 2A/P A/P P/A P/2A 2A/P A/P P/A ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design To ensure that the hogging bending moment at two points of suspension of a pile of length L equals the sagging moment at its centre, the distances of the points of suspension from either end, is 0.207 L 0.407 L 0.307 L 0.107 L 0.207 L 0.407 L 0.307 L 0.107 L ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. roof slab is designed as a two way slab if The slab is discontinuous at edges The slab is continuous over two supports The ratio of spans in two directions is less than 2 It supports live loads in both directions The slab is discontinuous at edges The slab is continuous over two supports The ratio of spans in two directions is less than 2 It supports live loads in both directions ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor) M/10√Q √(M/Q) M/100Q √(M/100Q) M/10√Q √(M/Q) M/100Q √(M/100Q) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Steel beam theory is used for Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete Design of simple steel beams Doubly reinforced beams ignoring compressive stress in concrete Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete Design of simple steel beams Doubly reinforced beams ignoring compressive stress in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The load stress of a section can be reduced by Decreasing the lever arm Replacing larger bars by greater number of small bars Replacing smaller bars by greater number of greater bars Increasing the total perimeter of bars Decreasing the lever arm Replacing larger bars by greater number of small bars Replacing smaller bars by greater number of greater bars Increasing the total perimeter of bars ANSWER DOWNLOAD EXAMIANS APP
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