RCC Structures Design Though the effective depth of a T-beam is the distance between the top compression edge to the centre of the tensile reinforcement, for heavy loads, it is taken as 1/8th of the span 1/12th of the span 1/10th of the span 1/16th of the span 1/8th of the span 1/12th of the span 1/10th of the span 1/16th of the span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are tread and rise respectively of a stair, then 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Pick up the true statement from the following: In the absence of beams, it is easier to paint All listed here In the absence of beams, it is easier to install piping Plain ceiling provides the best property diffusing light In the absence of beams, it is easier to paint All listed here In the absence of beams, it is easier to install piping Plain ceiling provides the best property diffusing light ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If permissible working stresses in steel and concrete are respectively 1400 kg/cm² and 80 kg/cm² and modular ratio is 18, in a beam reinforced in tension side and of width 30 cm and having effective depth 46 cm, the lever arms of the section, is 40 cm 39 cm 38 cm 37 cm 40 cm 39 cm 38 cm 37 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is Kx (1 - x/l) + bw K/x (1 + x/d) + bw Kx (1 + x/l) + bw All listed here Kx (1 - x/l) + bw K/x (1 + x/d) + bw Kx (1 + x/l) + bw All listed here ANSWER DOWNLOAD EXAMIANS APP
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