RCC Structures Design A ribbed slab is provided for Acoustic insulation All of these Thermal insulation A plain ceiling Acoustic insulation All of these Thermal insulation A plain ceiling ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a singly reinforced beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Steel possesses initial stresses when embedded in concrete Compression is borne entirely by concrete Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Steel possesses initial stresses when embedded in concrete Compression is borne entirely by concrete Elastic moduli for concrete and steel have different values within the limits of deformation of the beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/8a²bq ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Enlarged head of a supporting column of a flat slab is technically known as Top of the column Drop panel Supporting end of the column Capital Top of the column Drop panel Supporting end of the column Capital ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is K/x (1 + x/d) + bw Kx (1 + x/l) + bw Kx (1 - x/l) + bw All listed here K/x (1 + x/d) + bw Kx (1 + x/l) + bw Kx (1 - x/l) + bw All listed here ANSWER DOWNLOAD EXAMIANS APP
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