RCC Structures Design According to the steel beam theory of doubly reinforced beams Stress in tension steel equals the stress in compression steel Tension is resisted by tension steel Compression is resisted by compression steel All of the listed here Stress in tension steel equals the stress in compression steel Tension is resisted by tension steel Compression is resisted by compression steel All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the shear stress in a R.C.C. beam is All of these Greater than 20 kg/cm², the size of the section is changed Greater than 4 kg/cm², but less than 20 kg/cm², shear reinforcement is provided Equal or less than 5 kg/cm², no shear reinforcement is provided All of these Greater than 20 kg/cm², the size of the section is changed Greater than 4 kg/cm², but less than 20 kg/cm², shear reinforcement is provided Equal or less than 5 kg/cm², no shear reinforcement is provided ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If W is total load per unit area on a panel, D is the diameter of the column head, L is the span in two directions, then the sum of the maximum positive bending moment and average of the negative bending moment for the design of the span of a square flat slab, should not be less than WL/12 (L - 2D/3)² WL/10 (L - 2D/3)² WL/10 (L + 2D/3)² WL/12 (L - D/3)² WL/12 (L - 2D/3)² WL/10 (L - 2D/3)² WL/10 (L + 2D/3)² WL/12 (L - D/3)² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A column is regarded as long column if the ratio of its effective length and lateral dimension, exceeds 15 25 10 20 15 25 10 20 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If a bent tendon is required to balance a concentrated load W at the centre of the span L, the central dip h must be at least WL/3P WL/4P WL/P WL/2P WL/3P WL/4P WL/P WL/2P ANSWER DOWNLOAD EXAMIANS APP
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