RCC Structures Design If a bent tendon is required to balance a concentrated load W at the centre of the span L, the central dip h must be at least WL/4P WL/P WL/2P WL/3P WL/4P WL/P WL/2P WL/3P ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at the centre and from other two points 0.15 L from either end ; the maximum hogging moment will be WL²/60 WL²/90 WL²/15 WL²/30 WL²/60 WL²/90 WL²/15 WL²/30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Steel beam theory is used for Beams if shear exceeds 4 times allowable shear stress Doubly reinforced beams ignoring compressive stress in concrete Design of simple steel beams Steel beams encased in concrete Beams if shear exceeds 4 times allowable shear stress Doubly reinforced beams ignoring compressive stress in concrete Design of simple steel beams Steel beams encased in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the permissible compressive stress for a concrete in bending is C kg/m², the modular ratio is 2300/2C 2800/C 2800/C² 2800/3C 2300/2C 2800/C 2800/C² 2800/3C ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In testing a pile by load test, pile platform is loaded with one and half times the design load and a maximum settlement is noted. The load is gradually removed and the consequent rebound is measured. For a safe pile, the net settlement (i.e. total settlement minus rebound) per tonne of test load should not exceed 25 mm 20 mm 10 mm 15 mm 25 mm 20 mm 10 mm 15 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) ANSWER DOWNLOAD EXAMIANS APP
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