RCC Structures Design The Young's modulus of elasticity of steel, is 150 KN/mm² 200 KN/mm² 275 KN/mm² 250 KN/mm² 150 KN/mm² 200 KN/mm² 275 KN/mm² 250 KN/mm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The neutral axis of a T-beam exists At the bottom edge of the slab All listed here Within the flange Below the slab At the bottom edge of the slab All listed here Within the flange Below the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘H’ is the overall height of a retaining wall retaining a surcharge, the width of the base slab usually provided, is 0.3 H 0.4 H 0.5 H 0.7 H 0.3 H 0.4 H 0.5 H 0.7 H ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because Removal of cracks in the members due to shrinkage Its dimensions are not decided from the diagonal tensile stress All listed here Large size of long beams carrying large shear force need not be adopted Removal of cracks in the members due to shrinkage Its dimensions are not decided from the diagonal tensile stress All listed here Large size of long beams carrying large shear force need not be adopted ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If W is total load per unit area on a panel, D is the diameter of the column head, L is the span in two directions, then the sum of the maximum positive bending moment and average of the negative bending moment for the design of the span of a square flat slab, should not be less than WL/10 (L - 2D/3)² WL/12 (L - D/3)² WL/12 (L - 2D/3)² WL/10 (L + 2D/3)² WL/10 (L - 2D/3)² WL/12 (L - D/3)² WL/12 (L - 2D/3)² WL/10 (L + 2D/3)² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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