RCC Structures Design The maximum shear stress (q) in concrete of a reinforced cement concrete beam is Shear force/(Lever arm × Width) Width/(Lever arm × Shear force) (Shear force × Width)/Lever arm Lever arm/(Shear force × Width) Shear force/(Lever arm × Width) Width/(Lever arm × Shear force) (Shear force × Width)/Lever arm Lever arm/(Shear force × Width) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40,000 kg axially, the stress is 49.9 kg/cm² 100 kg/cm² 175 kg/cm² 250 kg/cm² 49.9 kg/cm² 100 kg/cm² 175 kg/cm² 250 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The stresses developed in concrete and steel in reinforced concrete beam 25 cm width and 70 cm effective depth, are 62.5 kg/cm² and 250 kg/cm² respectively. If m = 15, the depth of its neutral axis is 20 cm 25 cm 35 cm 30 cm 20 cm 25 cm 35 cm 30 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d and n are the effective depth and depth of the neutral axis respectively of a singly reinforced beam, the lever arm of the beam, is d - n/3 d + n/3 d n d - n/3 d + n/3 d n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design After pre-stressing process is completed, a loss of stress is due to Shrinkage of concrete Creep of concrete Elastic shortening of concrete All of the listed here Shrinkage of concrete Creep of concrete Elastic shortening of concrete All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design With usual notations the depth of the neutral axis of a balanced section, is given by mc/t = n/(d - n) mc/t = (d - n)/n t/mc = (d + n)/n t/mc = (d - n)/n mc/t = n/(d - n) mc/t = (d - n)/n t/mc = (d + n)/n t/mc = (d - n)/n ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS