RCC Structures Design Distribution of shear intensity over a rectangular section of a beam, follows: A parabolic curve A circular curve An elliptical curve A straight line A parabolic curve A circular curve An elliptical curve A straight line ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A short column 20 cm × 20 cm in section is reinforced with 4 bars whose area of cross section is 20 sq. cm. If permissible compressive stresses in concrete and steel are 40 kg/cm² and 300 kg/cm², the Safe load on the column, should not exceed 412,000 kg 4,120 kg 41,200 kg None of these 412,000 kg 4,120 kg 41,200 kg None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The minimum head room over a stair must be 230 cm 210 cm 200 cm 205 cm 230 cm 210 cm 200 cm 205 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of a two way slab simply supported on edges and having no provision to prevent the corners from lifting, is made by Rankine Grashoff formula Grashoff formula Marcus formula Rankine formula Rankine Grashoff formula Grashoff formula Marcus formula Rankine formula ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For initial estimate for a beam design, the width is assumed 1/30th of span 1/25th of span 1/20th of span 1/15th of span 1/30th of span 1/25th of span 1/20th of span 1/15th of span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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