RCC Structures Design If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be. Straight above centroidal axis Straight below centroidal axis Parabolic with convexity downward Parabolic with convexity upward Straight above centroidal axis Straight below centroidal axis Parabolic with convexity downward Parabolic with convexity upward ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is w (1 - cos φ)/h (1 + sin φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - cos φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - cos φ)/(1 + sin φ) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member Possesses internal stresses Is made of reinforced concrete Is made of concrete Is stressed after casting Possesses internal stresses Is made of reinforced concrete Is made of concrete Is stressed after casting ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Distribution of shear intensity over a rectangular section of a beam, follows: A circular curve A straight line A parabolic curve An elliptical curve A circular curve A straight line A parabolic curve An elliptical curve ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (b - a)²/4 M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (b - a)²/4 ANSWER DOWNLOAD EXAMIANS APP
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