RCC Structures Design If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be. Parabolic with convexity downward Straight below centroidal axis Parabolic with convexity upward Straight above centroidal axis Parabolic with convexity downward Straight below centroidal axis Parabolic with convexity upward Straight above centroidal axis ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor) M/10√Q √(M/Q) M/100Q √(M/100Q) M/10√Q √(M/Q) M/100Q √(M/100Q) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Columns may be made of plain concrete if their unsupported lengths do not exceed their least lateral dimension Two times Five times Three times Four times Two times Five times Three times Four times ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. beam of 25 cm width and 50 cm effective depth has a clear span of 6 meters and carries a U.D.L. of 3000 kg/m inclusive of its self weight. If the lever arm constant for the section is 0.865, the maximum intensity of shear stress, is 21.5 kg/cm² 8.3 kg/cm² 21.5 kg/cm² 7.6 kg/cm² 21.5 kg/cm² 8.3 kg/cm² 21.5 kg/cm² 7.6 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The width of the flange of a T-beam should be less than Breadth of the rib plus twelve times the thickness of the slab One-third of the effective span of the T-beam Least of the above Distance between the centers of T-beam Breadth of the rib plus twelve times the thickness of the slab One-third of the effective span of the T-beam Least of the above Distance between the centers of T-beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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