RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The load stress of a section can be reduced by Increasing the total perimeter of bars Replacing smaller bars by greater number of greater bars Replacing larger bars by greater number of small bars Decreasing the lever arm Increasing the total perimeter of bars Replacing smaller bars by greater number of greater bars Replacing larger bars by greater number of small bars Decreasing the lever arm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In testing a pile by load test, pile platform is loaded with one and half times the design load and a maximum settlement is noted. The load is gradually removed and the consequent rebound is measured. For a safe pile, the net settlement (i.e. total settlement minus rebound) per tonne of test load should not exceed 15 mm 25 mm 20 mm 10 mm 15 mm 25 mm 20 mm 10 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of the span to the overall depth does not exceed 10, the stiffness of the beam will ordinarily be satisfactory in case of a Simply supported beam None of these Continuous beam Cantilever beam Simply supported beam None of these Continuous beam Cantilever beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The advantage of reinforced concrete, is due to All listed here Economy because of less maintenance cost Monolithic character Fire-resisting and durability All listed here Economy because of less maintenance cost Monolithic character Fire-resisting and durability ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
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