RCC Structures Design The number of treads in a flight is equal to Risers minus one None of these Risers in the flight Risers plus one Risers minus one None of these Risers in the flight Risers plus one ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For the design of a simply supported T-beam the ratio of the effective span to the overall depth of the beam is limited to 25 10 20 15 25 10 20 15 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If a rectangular pre-stressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be 20 cm 15 cm 5 cm 10 cm 20 cm 15 cm 5 cm 10 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of different sizes, should not be less than One diameter of thinner bar Twice the diameter of thinner bar None of these One diameter of thicker bar One diameter of thinner bar Twice the diameter of thinner bar None of these One diameter of thicker bar ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If L is the effective span of a R.C.C. beam which is subjected to maximum shear qmax at the ends, the distance from either end over which stirrups for the shear, are provided, is (L/2) (1 - 5/qmax) (L/2) (1 - 2/qmax) (L/2) (1 - 3/qmax) (L/3) (1 - 5/qmax) (L/2) (1 - 5/qmax) (L/2) (1 - 2/qmax) (L/2) (1 - 3/qmax) (L/3) (1 - 5/qmax) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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