RCC Structures Design The number of treads in a flight is equal to Risers minus one Risers plus one None of these Risers in the flight Risers minus one Risers plus one None of these Risers in the flight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is All listed here Kx (1 + x/l) + bw K/x (1 + x/d) + bw Kx (1 - x/l) + bw All listed here Kx (1 + x/l) + bw K/x (1 + x/d) + bw Kx (1 - x/l) + bw ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The reinforced concrete beam which has width 25 cm, lever arm 40 cm, shear force 6t/cm², safe shear stress 5 kg/cm² and B.M. 24 mt, Needs redesigning Is safe in shear Is over safe in shear Is unsafe in shear Needs redesigning Is safe in shear Is over safe in shear Is unsafe in shear ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Pick up the true statement from the following: Plain ceiling provides the best property diffusing light All listed here In the absence of beams, it is easier to paint In the absence of beams, it is easier to install piping Plain ceiling provides the best property diffusing light All listed here In the absence of beams, it is easier to paint In the absence of beams, it is easier to install piping ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40,000 kg axially, the stress is 100 kg/cm² 175 kg/cm² 250 kg/cm² 49.9 kg/cm² 100 kg/cm² 175 kg/cm² 250 kg/cm² 49.9 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)² ANSWER DOWNLOAD EXAMIANS APP
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