RCC Structures Design The number of treads in a flight is equal to Risers in the flight Risers minus one Risers plus one None of these Risers in the flight Risers minus one Risers plus one None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For initial estimate for a beam design, the width is assumed 1/25th of span 1/20th of span 1/30th of span 1/15th of span 1/25th of span 1/20th of span 1/30th of span 1/15th of span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The transverse reinforcements provided at right angles to the main reinforcement All of these Resist the shrinkage stress Resist the temperature stresses Distribute the load All of these Resist the shrinkage stress Resist the temperature stresses Distribute the load ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of different sizes, should not be less than None of these Twice the diameter of thinner bar One diameter of thicker bar One diameter of thinner bar None of these Twice the diameter of thinner bar One diameter of thicker bar One diameter of thinner bar ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/8a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/4a²bq ANSWER DOWNLOAD EXAMIANS APP