RCC Structures Design An R.C.C beam of 25 cm width has a clear span of 5 metres and carries a U.D.L. of 2000 kg/m inclusive of its self weight. If the lever arm of the section is 45 cm., the beam is Needs revision of the section Is safe with stirrups and inclined members Is safe with stirrups Safe in shear Needs revision of the section Is safe with stirrups and inclined members Is safe with stirrups Safe in shear ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Spacing of stirrups in a rectangular beam, is Increased at the ends Decreased towards the centre of the beam Increased at the centre of the beam Kept constant throughout the length Increased at the ends Decreased towards the centre of the beam Increased at the centre of the beam Kept constant throughout the length ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 456, the reinforcement in a column should not be less than 0.7% and not more than 7% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.5% and not more than 5% of cross-sectional area 0.8% and not more than 8% of cross-sectional area 0.7% and not more than 7% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.5% and not more than 5% of cross-sectional area 0.8% and not more than 8% of cross-sectional area ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a singly reinforced beam, if the permissible stress in concrete reaches earlier than that in steel, the beam section is called Over reinforced section Critical section Under-reinforced section Economic section Over reinforced section Critical section Under-reinforced section Economic section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of R.C.C. cantilever beams, is based on the resultant force at Fixed end Free end Mid span Mid span and fixed support Fixed end Free end Mid span Mid span and fixed support ANSWER DOWNLOAD EXAMIANS APP
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