RCC Structures Design If the modular ratio is ‘m’, steel ratio is ‘r’ and overall depth of a beam is ‘d’, the depth of the critical neutral axis of the beam, is [m/(m - r)] d [(m + r)/m] d [(r - m)/m] d [m/(m + r)] d [m/(m - r)] d [(m + r)/m] d [(r - m)/m] d [m/(m + r)] d ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An under-reinforced section means Steel is provided at the underside only Steel will yield first Steel provided is insufficient Steel provided on one face only Steel is provided at the underside only Steel will yield first Steel provided is insufficient Steel provided on one face only ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If a rectangular pre-stressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be 5 cm 10 cm 20 cm 15 cm 5 cm 10 cm 20 cm 15 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An intermediate T-beam reinforced with two layers of tensile steel with clear cover 13 cm encased with the floor of a hall 12 meters by 7 meters, is spaced at 3 meters from adjoining beams and if the width of the beam is 20 cm, the breadth of the flange is 233 cm 236 cm 300 cm 176 cm 233 cm 236 cm 300 cm 176 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C beam of 25 cm width has a clear span of 5 metres and carries a U.D.L. of 2000 kg/m inclusive of its self weight. If the lever arm of the section is 45 cm., the beam is Is safe with stirrups and inclined members Safe in shear Is safe with stirrups Needs revision of the section Is safe with stirrups and inclined members Safe in shear Is safe with stirrups Needs revision of the section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ ANSWER DOWNLOAD EXAMIANS APP
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