RCC Structures Design The live load to be considered for an inaccessible roof, is 150 kg/cm² 75 kg/m² Nil 200 kg/m² 150 kg/cm² 75 kg/m² Nil 200 kg/m² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The length of the lap in a compression member is kept greater than bar diameter x (Permissible stress in bar / Five times the bond stress) or 12 bar diameters 18 bar diameters 24 bar diameters 30 bar diameters 12 bar diameters 18 bar diameters 24 bar diameters 30 bar diameters ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 14 cm² 17 cm² 15 cm² 16 cm² 14 cm² 17 cm² 15 cm² 16 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are tread and rise respectively of a stair, then 2R + T = 60 R + 2T = 60 2R + T = 30 R + 2T= 30 2R + T = 60 R + 2T = 60 2R + T = 30 R + 2T= 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Based on punching shear consideration, the overall depth of a combined footing under a column A, is (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) None of these (Area of the column A × Safe punching stress)/Load on column A (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) None of these (Area of the column A × Safe punching stress)/Load on column A ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² ANSWER DOWNLOAD EXAMIANS APP
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