RCC Structures Design The live load to be considered for an inaccessible roof, is 75 kg/m² Nil 150 kg/cm² 200 kg/m² 75 kg/m² Nil 150 kg/cm² 200 kg/m² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The weight of a foundation is assumed as 12% of wall weight 7% of wall weight 10% of wall weight 5% of wall weight 12% of wall weight 7% of wall weight 10% of wall weight 5% of wall weight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Total pressure on the vertical face of a retaining wall of height ‘h’ per unit run exerted by the retained earth weighing ‘w’ per unit volume, is wh² [(1 - sin φ)/(1 + sin φ)] wh [(1 - sin φ)/(1 + sin φ)] wh² [(1 - sin φ)/2(1 + sin φ)] wh² [(1 - sin φ)/3(1 + sin φ)] wh² [(1 - sin φ)/(1 + sin φ)] wh [(1 - sin φ)/(1 + sin φ)] wh² [(1 - sin φ)/2(1 + sin φ)] wh² [(1 - sin φ)/3(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 456, the reinforcement in a column should not be less than 0.5% and not more than 5% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.8% and not more than 8% of cross-sectional area 0.7% and not more than 7% of cross-sectional area 0.5% and not more than 5% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.8% and not more than 8% of cross-sectional area 0.7% and not more than 7% of cross-sectional area ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a combined footing for two columns carrying unequal loads, the maximum hogging bending moment occurs at More loaded column A point of zero shear force Less loaded column A point of the maximum shear force More loaded column A point of zero shear force Less loaded column A point of the maximum shear force ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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