A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is

RCC Structures Design
A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is

15 cm²

17 cm²

14 cm²

16 cm²

15 cm²

17 cm²

14 cm²

16 cm²

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RCC Structures Design
The design of heel slab of a retaining wall is based on the maximum bending moment due to:

Weight of the soil above it

Its own weight

Load of the surcharge, if any

All listed here

Weight of the soil above it

Its own weight

Load of the surcharge, if any

All listed here

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RCC Structures Design
The advantage of reinforced concrete, is due to

All listed here

Fire-resisting and durability

Monolithic character

Economy because of less maintenance cost

All listed here

Fire-resisting and durability

Monolithic character

Economy because of less maintenance cost

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RCC Structures Design
If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be.

Straight above centroidal axis

Straight below centroidal axis

Parabolic with convexity downward

Parabolic with convexity upward

Straight above centroidal axis

Straight below centroidal axis

Parabolic with convexity downward

Parabolic with convexity upward

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RCC Structures Design
If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is

Kx (1 + x/l) + bw

K/x (1 + x/d) + bw

All listed here

Kx (1 - x/l) + bw

Kx (1 + x/l) + bw

K/x (1 + x/d) + bw

All listed here

Kx (1 - x/l) + bw

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RCC Structures Design
In a beam the local bond stress Sb, is equal to

Total perimeter of reinforcement/(Leaver arm × Shear force)

Leaver arm/(Shear force × Total perimeter of reinforcement)

Shear force/(Leaver arm × Total perimeter of reinforcement)

Leaver arm/(Bending moment × Total perimeter of reinforcement)

Total perimeter of reinforcement/(Leaver arm × Shear force)

Leaver arm/(Shear force × Total perimeter of reinforcement)

Shear force/(Leaver arm × Total perimeter of reinforcement)

Leaver arm/(Bending moment × Total perimeter of reinforcement)

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RCC Structures Design

RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is

RCC Structures Design The design of heel slab of a retaining wall is based on the maximum bending moment due to:

RCC Structures Design The advantage of reinforced concrete, is due to

RCC Structures Design If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be.

RCC Structures Design In a beam the local bond stress Sb, is equal to

RCC Structures Design
A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is

RCC Structures Design
The design of heel slab of a retaining wall is based on the maximum bending moment due to:

RCC Structures Design
The advantage of reinforced concrete, is due to

RCC Structures Design
If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be.

RCC Structures Design
In a beam the local bond stress Sb, is equal to