RCC Structures Design The spacing of transverse reinforcement of column is decided by the following consideration. Forty-eight times the diameter of transverse reinforcement Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column The least lateral dimension of the column All listed here Forty-eight times the diameter of transverse reinforcement Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column The least lateral dimension of the column All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A T-beam behaves as a rectangular beam of a width equal to its flange if its neutral axis Coincides the geometrical centre of the beam Remains within the flange Remains below the slab None of these Coincides the geometrical centre of the beam Remains within the flange Remains below the slab None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t (t + c)/n = (d + n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Enlarged head of a supporting column of a flat slab is technically known as Top of the column Drop panel Capital Supporting end of the column Top of the column Drop panel Capital Supporting end of the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The length of lap in tension reinforcement should not be less than the bar diameter × (actual tension / four times the permissible average bond stress) if it is more than 24 bar diameters 30 bar diameters 36 bar diameters 18 bar diameters 24 bar diameters 30 bar diameters 36 bar diameters 18 bar diameters ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
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