RCC Structures Design A singly reinforced beam has breadth b, effective depth d, depth of neutral axis n and critical neutral axis n?. If fc and ft are permissible compressive and tensile stresses, the moment to resistance of the beam, is All listed here ½ n₁ (1 - n₁/3) cbd² bn (fc/2) (d - n/3) Atft (d - n/3) All listed here ½ n₁ (1 - n₁/3) cbd² bn (fc/2) (d - n/3) Atft (d - n/3) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A reinforced concrete cantilever beam is 3.6 m long, 25 cm wide and has its lever arm 40 cm. It carries a load of 1200 kg at its free end and vertical stirrups can carry 1800 kg. Assuming concrete to carry one-third of the diagonal tension and ignoring the weight of the beam, the number of shear stirrups required, is 40 35 45 30 40 35 45 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is Stress in concrete × area of concrete + Stress in steel × area of steel None of these Stress in concrete × area of concrete Stress in steel × area of steel Stress in concrete × area of concrete + Stress in steel × area of steel None of these Stress in concrete × area of concrete Stress in steel × area of steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design After pre-stressing process is completed, a loss of stress is due to Elastic shortening of concrete Creep of concrete Shrinkage of concrete All of the listed here Elastic shortening of concrete Creep of concrete Shrinkage of concrete All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm², the share stirrups are provided for a distance ‘x’ from either end where, ‘x’ is 100 cm 200 cm 50 cm 150 cm 100 cm 200 cm 50 cm 150 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by (5/6) (r²/1 + r⁴) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r²/1 + r⁴) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r²) M (5/6) (r²/1 + r³) M ANSWER DOWNLOAD EXAMIANS APP