RCC Structures Design Distribution reinforcement in a simply supported slab, is provided to distribute Shrinkage stress All listed here Load Temperature stress Shrinkage stress All listed here Load Temperature stress ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are effective lateral loadings at the bottom and top exerted by a level earth subjected to a super-load on the vertical face of height h of a retaining wall, the horizontal pressure p per unit length of the wall, is (p₁ - p₂) ⅔h [(p₁ - p₂)/2] h [(p₁ + p₂)/4] h [(p₁ + p₂)/2] h (p₁ - p₂) ⅔h [(p₁ - p₂)/2] h [(p₁ + p₂)/4] h [(p₁ + p₂)/2] h ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design By over-reinforcing a beam, the moment of resistance can be increased not more than 25 % 10 % 20 % 15 % 25 % 10 % 20 % 15 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is Stress in steel × area of steel Stress in concrete × area of concrete Stress in concrete × area of concrete + Stress in steel × area of steel None of these Stress in steel × area of steel Stress in concrete × area of concrete Stress in concrete × area of concrete + Stress in steel × area of steel None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design On piles, the drop must be at least 80 cm 123 cm 124 cm 120 cm 80 cm 123 cm 124 cm 120 cm ANSWER DOWNLOAD EXAMIANS APP
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