RCC Structures Design If diameter of a reinforcement bar is d, the anchorage value of the hook is 4d 16d 12d 8d 4d 16d 12d 8d ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Steel beam theory is used for Doubly reinforced beams ignoring compressive stress in concrete Design of simple steel beams Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete Doubly reinforced beams ignoring compressive stress in concrete Design of simple steel beams Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a cantilever retaining wall without a heel slab All listed here Thickness of the stem is kept same throughout Width of the base slab is kept 0.7 time the total height of the wall Base slab is made 10 cm thicker than the stem All listed here Thickness of the stem is kept same throughout Width of the base slab is kept 0.7 time the total height of the wall Base slab is made 10 cm thicker than the stem ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A flat slab is supported On beams On beams and columns On columns On columns monolithically built with slab On beams On beams and columns On columns On columns monolithically built with slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a wall on either side of a lintel opening is at least half of its effective span L, the load W carried by the lintel is equivalent to the weight of brickwork contained in an equilateral triangle, producing a maximum bending moment WL/2 WL/8 WL/4 WL/6 WL/2 WL/8 WL/4 WL/6 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/4 M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/4 ANSWER DOWNLOAD EXAMIANS APP
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