RCC Structures Design Bottom bars under the columns are extended into the interior of the footing slab to a distance greater than 42 diameters from the centre of the column 24 diameters from the centre of the column 42 diameters from the inner edge of the column 42 diameters from the outer edge of the column 42 diameters from the centre of the column 24 diameters from the centre of the column 42 diameters from the inner edge of the column 42 diameters from the outer edge of the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Distribution reinforcement in a simply supported slab, is provided to distribute Temperature stress All listed here Load Shrinkage stress Temperature stress All listed here Load Shrinkage stress ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A very comfortable type of stairs is Dog legged Open newel Geometrical Straight Dog legged Open newel Geometrical Straight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is w (1 - cos φ)/h (1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a slab, the pitch of the main reinforcement should not exceed its effective depth Four times Two times Five times Three times Four times Two times Five times Three times ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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