RCC Structures Design If the size of a column is reduced above the floor, the main bars of the columns, are Bent inward at the floor level Continued up Stopped just below the floor level and separate lap bars provided All of the listed here Bent inward at the floor level Continued up Stopped just below the floor level and separate lap bars provided All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The radius of a bar bend to form a hook, should not be less than Five times the diameter Twice the diameter Thrice the diameter Four times the diameter Five times the diameter Twice the diameter Thrice the diameter Four times the diameter ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A circular slab subjected to external loading, deflects to form a Ellipsoid None of these Semi-hemisphere Paraboloid Ellipsoid None of these Semi-hemisphere Paraboloid ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design High strength concrete is used in pre-stressed member To overcome high bearing stresses developed at the ends To provide high bond stresses To overcome bursting stresses at the ends All listed here To overcome high bearing stresses developed at the ends To provide high bond stresses To overcome bursting stresses at the ends All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The transverse reinforcements provided at right angles to the main reinforcement Distribute the load All of these Resist the temperature stresses Resist the shrinkage stress Distribute the load All of these Resist the temperature stresses Resist the shrinkage stress ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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