RCC Structures Design If the size of a column is reduced above the floor, the main bars of the columns, are All of the listed here Bent inward at the floor level Stopped just below the floor level and separate lap bars provided Continued up All of the listed here Bent inward at the floor level Stopped just below the floor level and separate lap bars provided Continued up ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 14 cm² 16 cm² 17 cm² 15 cm² 14 cm² 16 cm² 17 cm² 15 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the bearing capacity of soil is 10 tonnes/cm² and the projection of plain concrete footing from walls, is a cm, the depth D of footing is D = 0.775 √a D = 0.775 a² D = 0.0775 a D = 0.775 a D = 0.775 √a D = 0.775 a² D = 0.0775 a D = 0.775 a ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For the design of a simply supported T-beam the ratio of the effective span to the overall depth of the beam is limited to 20 10 15 25 20 10 15 25 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Steel beam theory is used for Design of simple steel beams Doubly reinforced beams ignoring compressive stress in concrete Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete Design of simple steel beams Doubly reinforced beams ignoring compressive stress in concrete Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design With usual notations the depth of the neutral axis of a balanced section, is given by mc/t = n/(d - n) t/mc = (d - n)/n t/mc = (d + n)/n mc/t = (d - n)/n mc/t = n/(d - n) t/mc = (d - n)/n t/mc = (d + n)/n mc/t = (d - n)/n ANSWER DOWNLOAD EXAMIANS APP
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