RCC Structures Design Dimensions of a beam need be changed if the shear stress is more than 25 kg/cm² 20 kg/cm² 15 kg/cm² 10 kg/cm² 25 kg/cm² 20 kg/cm² 15 kg/cm² 10 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (c - a)/4 M = pb (b + a)/8 M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b - a)²/4 M = pb (c - a)/4 M = pb (b + a)/8 M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b - a)²/4 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A short column 20 cm × 20 cm in section is reinforced with 4 bars whose area of cross section is 20 sq. cm. If permissible compressive stresses in concrete and steel are 40 kg/cm² and 300 kg/cm², the Safe load on the column, should not exceed 4,120 kg None of these 41,200 kg 412,000 kg 4,120 kg None of these 41,200 kg 412,000 kg ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to the tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The maximum stress ‘f’ in the beam, subjected to a maximum bending moment ‘M’, is f = (P/A) + (M/Z) f = (P/A) + (M/6Z) f = (A/P) + (M/Z) f = (P/'+ (Z/M) f = (P/A) + (M/Z) f = (P/A) + (M/6Z) f = (A/P) + (M/Z) f = (P/'+ (Z/M) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a simply supported slab, alternate bars are curtailed at 1/7th of the span 1/6th of the span 1/5th of the span 1/4th of the span 1/7th of the span 1/6th of the span 1/5th of the span 1/4th of the span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of transverse reinforcement of columns should be equal to one-fourth of the diameter of the main steel rods but not less than 7 mm 6 mm 5 mm 4 mm 7 mm 6 mm 5 mm 4 mm ANSWER DOWNLOAD EXAMIANS APP
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