RCC Structures Design Dimensions of a beam need be changed if the shear stress is more than 15 kg/cm² 20 kg/cm² 25 kg/cm² 10 kg/cm² 15 kg/cm² 20 kg/cm² 25 kg/cm² 10 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If depth of slab is 10 cm, width of web 30 cm, depth of web 50 cm, centre to centre distance of beams 3 m, effective span of beams 6 m, the effective flange width of the beam, is 200 cm 150 cm 300 cm 100 cm 200 cm 150 cm 300 cm 100 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at the centre and from other two points 0.15 L from either end ; the maximum hogging moment will be WL²/90 WL²/15 WL²/60 WL²/30 WL²/90 WL²/15 WL²/60 WL²/30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is f = (P/A) - (M/6Z) f = (A/P) - (M/Z) f = (P/A) - (M/Z) f = (P/'- (Z/M) f = (P/A) - (M/6Z) f = (A/P) - (M/Z) f = (P/A) - (M/Z) f = (P/'- (Z/M) ANSWER DOWNLOAD EXAMIANS APP
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