RCC Structures Design Dimensions of a beam need be changed if the shear stress is more than 10 kg/cm² 15 kg/cm² 25 kg/cm² 20 kg/cm² 10 kg/cm² 15 kg/cm² 25 kg/cm² 20 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If jd is the lever arm and ΣO is the total perimeter of reinforcement of an R.C.C. beam, the bond stress at the section having Q shear force, is Q/jdƩO Q/2jdƩO 2 × Q/jdƩO Q/3jdƩO Q/jdƩO Q/2jdƩO 2 × Q/jdƩO Q/3jdƩO ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 16 cm² 17 cm² 15 cm² 14 cm² 16 cm² 17 cm² 15 cm² 14 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The minimum thickness of a flat slab is taken L/36 for interior panels without drop All listed here L/36 for end panels without drops L/32 for end panels without drops L/36 for interior panels without drop All listed here L/36 for end panels without drops L/32 for end panels without drops ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The load stress of a section can be reduced by Increasing the total perimeter of bars Replacing larger bars by greater number of small bars Replacing smaller bars by greater number of greater bars Decreasing the lever arm Increasing the total perimeter of bars Replacing larger bars by greater number of small bars Replacing smaller bars by greater number of greater bars Decreasing the lever arm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
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