RCC Structures Design Dimensions of a beam need be changed if the shear stress is more than 25 kg/cm² 15 kg/cm² 10 kg/cm² 20 kg/cm² 25 kg/cm² 15 kg/cm² 10 kg/cm² 20 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The design of heel slab of a retaining wall is based on the maximum bending moment due to: Load of the surcharge, if any All listed here Weight of the soil above it Its own weight Load of the surcharge, if any All listed here Weight of the soil above it Its own weight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A foundation rests on Sub-grade Foundation soil Both B and C Base of the foundation Sub-grade Foundation soil Both B and C Base of the foundation ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/Sb l = dt/2Sb l = dt/4Sb l = dt/3Sb l = dt/Sb l = dt/2Sb l = dt/4Sb l = dt/3Sb ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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