RCC Structures Design Dimensions of a beam need be changed if the shear stress is more than 20 kg/cm² 25 kg/cm² 15 kg/cm² 10 kg/cm² 20 kg/cm² 25 kg/cm² 15 kg/cm² 10 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to I.S. : 456, slabs which span in two directions with corners held down, are assumed to be divided in each direction into middle strips and edge strips such that the width of the middle strip, is Two-third of the width of the slab Half of the width of the slab Four-fifth of the width of the slab Three-fourth of the width of the slab Two-third of the width of the slab Half of the width of the slab Four-fifth of the width of the slab Three-fourth of the width of the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a slab, the pitch of the main reinforcement should not exceed its effective depth Two times Four times Five times Three times Two times Four times Five times Three times ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a combined footing if shear stress exceeds 5 kg/cm², the nominal stirrups provided are: 12 legged 8 legged 10 legged 6 legged 12 legged 8 legged 10 legged 6 legged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of transverse reinforcement of columns should be equal to one-fourth of the diameter of the main steel rods but not less than 5 mm 6 mm 4 mm 7 mm 5 mm 6 mm 4 mm 7 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
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