RCC Structures Design Dimensions of a beam need be changed if the shear stress is more than 20 kg/cm² 10 kg/cm² 25 kg/cm² 15 kg/cm² 20 kg/cm² 10 kg/cm² 25 kg/cm² 15 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor) √(M/100Q) √(M/Q) M/10√Q M/100Q √(M/100Q) √(M/Q) M/10√Q M/100Q ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. beam of 6 m span is 30 cm wide and has a lever arm of 55 cm. If it carries a U.D.L. of 12 t per m and allowable shear stress is 5 kg/cm², the beam Needs revision of section Is safe in shear Is safe with stirrups Is safe with stirrups and inclined bars Needs revision of section Is safe in shear Is safe with stirrups Is safe with stirrups and inclined bars ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the width of the foundation for two equal columns is restricted, the shape of the footing generally adopted, is Rectangular Square Triangular Trapezoidal Rectangular Square Triangular Trapezoidal ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of a two way slab simply supported on edges and having no provision to prevent the corners from lifting, is made by Rankine formula Rankine Grashoff formula Marcus formula Grashoff formula Rankine formula Rankine Grashoff formula Marcus formula Grashoff formula ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/4abq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq D = W (a - b)/4a²bq D = W (a² - b²)/4abq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq D = W (a - b)/4a²bq ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS