RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/4Sb l = dt/2Sb l = dt/Sb l = dt/3Sb l = dt/4Sb l = dt/2Sb l = dt/Sb l = dt/3Sb ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The section of a reinforced beam where most distant concrete fibre in compression and tension in steel attains permissible stresses simultaneously, is called Balanced section Critical section All listed here Economic section Balanced section Critical section All listed here Economic section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The Young's modulus of elasticity of steel, is 150 KN/mm² 200 KN/mm² 275 KN/mm² 250 KN/mm² 150 KN/mm² 200 KN/mm² 275 KN/mm² 250 KN/mm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (b + a)/8 ANSWER DOWNLOAD EXAMIANS APP
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