RCC Structures Design The minimum cube strength of concrete used for a pre-stressed member, is 50 kg/cm² 250 kg/cm² 350 kg/cm² 150 kg/cm² 50 kg/cm² 250 kg/cm² 350 kg/cm² 150 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the tendon is placed at an eccentricity e below the centroidal axis of the longitudinal axis of a rectangular beam (sectional modulus Z and stressed load P in tendon) the stress at the extreme top edge Is increased by PZ/e Is decreased by Pe/Z Is increased by Pe/Z Remains unchanged Is increased by PZ/e Is decreased by Pe/Z Is increased by Pe/Z Remains unchanged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the bearing capacity of soil is 10 tonnes/cm² and the projection of plain concrete footing from walls, is a cm, the depth D of footing is D = 0.775 a² D = 0.775 √a D = 0.775 a D = 0.0775 a D = 0.775 a² D = 0.775 √a D = 0.775 a D = 0.0775 a ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For initial estimate for a beam design, the width is assumed 1/25th of span 1/30th of span 1/15th of span 1/20th of span 1/25th of span 1/30th of span 1/15th of span 1/20th of span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The weight of a foundation is assumed as 5% of wall weight 7% of wall weight 10% of wall weight 12% of wall weight 5% of wall weight 7% of wall weight 10% of wall weight 12% of wall weight ANSWER DOWNLOAD EXAMIANS APP
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