RCC Structures Design In favourable circumstances a 15 cm concrete cube after 28 days, attains a maximum crushing strength 400 kg/cm² 100 kg/cm² 200 kg/cm² 300 kg/cm² 400 kg/cm² 100 kg/cm² 200 kg/cm² 300 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The spacing of transverse reinforcement of column is decided by the following consideration. Forty-eight times the diameter of transverse reinforcement The least lateral dimension of the column All listed here Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column Forty-eight times the diameter of transverse reinforcement The least lateral dimension of the column All listed here Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The neutral axis of a T-beam exists At the bottom edge of the slab Within the flange Below the slab All listed here At the bottom edge of the slab Within the flange Below the slab All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A T-beam behaves as a rectangular beam of a width equal to its flange if its neutral axis Coincides the geometrical centre of the beam Remains within the flange None of these Remains below the slab Coincides the geometrical centre of the beam Remains within the flange None of these Remains below the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design High strength concrete is used in pre-stressed member To overcome bursting stresses at the ends To overcome high bearing stresses developed at the ends To provide high bond stresses All listed here To overcome bursting stresses at the ends To overcome high bearing stresses developed at the ends To provide high bond stresses All listed here ANSWER DOWNLOAD EXAMIANS APP
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