RCC Structures Design In favourable circumstances a 15 cm concrete cube after 28 days, attains a maximum crushing strength 400 kg/cm² 100 kg/cm² 300 kg/cm² 200 kg/cm² 400 kg/cm² 100 kg/cm² 300 kg/cm² 200 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by (5/6) (r²/1 + r⁴) M (5/6) (r²/1 + r²) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r²/1 + r⁴) M (5/6) (r²/1 + r²) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r³) M ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The width of the rib of a T-beam, is generally kept between 1/3 to 2/3 of rib depth 1/3 to 1/2 of rib depth 1/7 to 1/3 of rib depth 1/2 to 3/4 of rib depth 1/3 to 2/3 of rib depth 1/3 to 1/2 of rib depth 1/7 to 1/3 of rib depth 1/2 to 3/4 of rib depth ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed rectangular beam which carries two concentrated loads W at L/3 from either end, is provided with a bent tendon with tension P such that central one-third portion of the tendon remains parallel to the longitudinal axis, the maximum dip h is WL/P WL/3P WL/2P WL/4P WL/P WL/3P WL/2P WL/4P ANSWER DOWNLOAD EXAMIANS APP
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