RCC Structures Design To ensure uniform pressure distribution, the thickness of the foundation, is Kept zero at the edge Decreased gradually towards the edge Kept uniform throughout Increased gradually towards the edge Kept zero at the edge Decreased gradually towards the edge Kept uniform throughout Increased gradually towards the edge ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. beam of 6 m span is 30 cm wide and has a lever arm of 55 cm. If it carries a U.D.L. of 12 t per m and allowable shear stress is 5 kg/cm², the beam Needs revision of section Is safe with stirrups and inclined bars Is safe in shear Is safe with stirrups Needs revision of section Is safe with stirrups and inclined bars Is safe in shear Is safe with stirrups ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A ribbed slab is provided for A plain ceiling All of these Acoustic insulation Thermal insulation A plain ceiling All of these Acoustic insulation Thermal insulation ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the effective length of a 32 cm diameter R.C.C. column is 4.40 m, its slenderness ratio, is 55 50 45 40 55 50 45 40 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Distribution reinforcement in a simply supported slab, is provided to distribute Shrinkage stress All listed here Temperature stress Load Shrinkage stress All listed here Temperature stress Load ANSWER DOWNLOAD EXAMIANS APP
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