RCC Structures Design After pre-stressing process is completed, a loss of stress is due to Shrinkage of concrete Elastic shortening of concrete Creep of concrete All of the listed here Shrinkage of concrete Elastic shortening of concrete Creep of concrete All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to I.S. : 456, slabs which span in two directions with corners held down, are assumed to be divided in each direction into middle strips and edge strips such that the width of the middle strip, is Half of the width of the slab Four-fifth of the width of the slab Three-fourth of the width of the slab Two-third of the width of the slab Half of the width of the slab Four-fifth of the width of the slab Three-fourth of the width of the slab Two-third of the width of the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of R.C.C. cantilever beams, is based on the resultant force at Mid span and fixed support Mid span Fixed end Free end Mid span and fixed support Mid span Fixed end Free end ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The weight of a foundation is assumed as 10% of wall weight 12% of wall weight 7% of wall weight 5% of wall weight 10% of wall weight 12% of wall weight 7% of wall weight 5% of wall weight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n ANSWER DOWNLOAD EXAMIANS APP
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