RCC Structures Design According to I.S.: 456, 1978 the thickness of reinforced concrete footing on piles at its edges, is kept less than 40 cm 30 cm 20 cm 75 cm 40 cm 30 cm 20 cm 75 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the size of a column is reduced above the floor, the main bars of the columns, are Stopped just below the floor level and separate lap bars provided Bent inward at the floor level Continued up All of the listed here Stopped just below the floor level and separate lap bars provided Bent inward at the floor level Continued up All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The thickness of base slab of a retaining wall generally provided, is One half of the width of the stem at the bottom One fourth of the width of the steam at the bottom One-third of the width of the stem at the bottom Width of the stem at the bottom One half of the width of the stem at the bottom One fourth of the width of the steam at the bottom One-third of the width of the stem at the bottom Width of the stem at the bottom ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a combined footing if shear stress exceeds 5 kg/cm², the nominal stirrups provided are: 8 legged 6 legged 12 legged 10 legged 8 legged 6 legged 12 legged 10 legged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design On an absolutely rigid foundation base, the pressure will Be uniform Be more at the edges of the foundation Be zero at the centre of the foundation Not be uniform Be uniform Be more at the edges of the foundation Be zero at the centre of the foundation Not be uniform ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) ANSWER DOWNLOAD EXAMIANS APP
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