Theory of Machine The relation between number of links (l) and number of joints (j) in a kinematic chain is l = (1/2).(j + 2) l = (3/4).(j + 3) l = j + 4 l = (2/3).(j + 2) l = (1/2).(j + 2) l = (3/4).(j + 3) l = j + 4 l = (2/3).(j + 2) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the two elements of a pair have a surface contact when relative motion takes place and the surface of one element slides over the surface of the other, the pair formed is known as a Lower pair Higher pair Force-closed pair Self-closed pair Lower pair Higher pair Force-closed pair Self-closed pair ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a steam engine, the link constitutes a All of these Crank pin, crankshaft and flywheel Piston, piston rod and cross-head Connecting rod with big and small end brasses, caps and bolts All of these Crank pin, crankshaft and flywheel Piston, piston rod and cross-head Connecting rod with big and small end brasses, caps and bolts ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a four-bar chain it is required to give an oscillatory motion to the follower for a continuous rotation of the crank. For the lengths of 50 mm of crank and 70 mm of the follower, determine theoretical maximum length of coupler. The minimum length of the coupler will be Slightly more than 45 mm 95 mm Slightly less than 45 mm 45 mm Slightly more than 45 mm 95 mm Slightly less than 45 mm 45 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The inversion of a mechanism is Changing of a higher pair to a lower pair Obtained by reversing the input and output motion Turning its upside down Obtained by fixing different links in a kinematic chain Changing of a higher pair to a lower pair Obtained by reversing the input and output motion Turning its upside down Obtained by fixing different links in a kinematic chain ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a flat collar bearing, considering uniform wear, is (where r₁ and r₂ = External and internal radii of collar respectively) (2/3) μ W (r₁ + r₂) (1/2) μ W (r₁ + r₂) (2/3) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3) μ W (r₁ + r₂) (1/2) μ W (r₁ + r₂) (2/3) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] ANSWER DOWNLOAD EXAMIANS APP
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