Engineering Mechanics The motion of a particle round a fixed axis is Translatory Circular Rotary Translatory as well as rotary Translatory Circular Rotary Translatory as well as rotary ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The point, through which the whole weight of the body acts, irrespective of its position, is known as Moment of inertia Center of mass Center of percussion Center of gravity Moment of inertia Center of mass Center of percussion Center of gravity ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its vertex and parallel to the base, is __________ than that passing through its C.G. and parallel to the base. Four times Six times Nine times Two times Four times Six times Nine times Two times ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The time of flight (t) of a projectile on an upward inclined plane is(where u = Velocity of projection, α = Angle of projection, and β = Inclination of the plane with the horizontal.) t = 2u sin (α - β)/g cos β t = g cos β/2u sin (α - β) t = 2u sin (α + β)/g cos β t = g cos β/2u sin (α + β) t = 2u sin (α - β)/g cos β t = g cos β/2u sin (α - β) t = 2u sin (α + β)/g cos β t = g cos β/2u sin (α + β) ANSWER DOWNLOAD EXAMIANS APP
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