Engineering Mechanics The motion of a particle round a fixed axis is Circular Translatory Rotary Translatory as well as rotary Circular Translatory Rotary Translatory as well as rotary ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The impact between two lead spheres is approximately equal to an __________ impact. Solid Elastic Inelastic None of these Solid Elastic Inelastic None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is (kG² + h²)/h h/(kG² + h²) (kG² + h²)/h² h²/(kG² + h²) (kG² + h²)/h h/(kG² + h²) (kG² + h²)/h² h²/(kG² + h²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P - m.a = 0 P/m.a = 0 P + m.a = 0 P × m.a = 0 P - m.a = 0 P/m.a = 0 P + m.a = 0 P × m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The law of motion involved in the recoil of gun is Newton's first law of motion None of these Newton's third law of motion Newton's second law of motion Newton's first law of motion None of these Newton's third law of motion Newton's second law of motion ANSWER DOWNLOAD EXAMIANS APP
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