Engineering Mechanics The three forces of 100 N, 200 N and 300 N have their lines of action parallel to each other but act in the opposite directions. These forces are known as Unlike parallel forces Coplanar concurrent forces Coplanar non-concurrent forces Like parallel forces Unlike parallel forces Coplanar concurrent forces Coplanar non-concurrent forces Like parallel forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Non-coplanar concurrent forces are those forces which Do not meet at one point and their lines of action do not lie on the same plane Meet at one point, but their lines of action do not lie on the same plane Do not meet at one point, but their lines of action lie on the same plane Meet at one point and their lines of action also lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane Meet at one point, but their lines of action do not lie on the same plane Do not meet at one point, but their lines of action lie on the same plane Meet at one point and their lines of action also lie on the same plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Concurrent forces are those forces whose lines of action Lie on the same line None of these Meet at one point Meet on the same plane Lie on the same line None of these Meet at one point Meet on the same plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a sphere of mass 'm' and radius 'r', about an axis tangential to it, is 7mr²/5 2mr²/3 7mr²/3 2mr²/5 7mr²/5 2mr²/3 7mr²/3 2mr²/5 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS