Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG + Ah2
IP = IG - Ah2
IP = IG / Ah2
IP = Ah2 / IG

ANSWER DOWNLOAD EXAMIANS APP

Engineering Mechanics
The principle of transmissibility of forces states that, when a force acts upon a body, its effect is

Minimum, if it acts at the center of gravity of the body
Maximum, if it acts at the center of gravity of the body
Different at different points on its line of action
Same at every point on its line of action

ANSWER DOWNLOAD EXAMIANS APP

Engineering Mechanics
Varingon's theorem of moments states that if a number of coplanar forces acting on a particle are in equilibrium, then

The algebraic sum of their moments about any point is equal to the moment of their resultant force about the same point
Their algebraic sum is zero
Their lines of action are at equal distances
The algebraic sum of their moments about any point in their plane is zero

ANSWER DOWNLOAD EXAMIANS APP