According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG - Ah2

IP = IG / Ah2

IP = IG + Ah2

IP = Ah2 / IG

IP = IG - Ah2

IP = IG / Ah2

IP = IG + Ah2

IP = Ah2 / IG

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Engineering Mechanics
The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is

tanθ

cosecθ

sinθ

cosθ

tanθ

cosecθ

sinθ

cosθ

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Engineering Mechanics
The C.G. of a solid hemisphere lies on the central radius 3r

At distance — from the plane base 3r

At distance — from the plane base

At distance — from the plane base 3r

At distance — from the plane base

At distance — from the plane base 3r

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Engineering Mechanics
A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act

Zero at its upper end

Upward at its upper end

Downward at its upper end

Perpendicular to the wall at its upper end

Zero at its upper end

Upward at its upper end

Downward at its upper end

Perpendicular to the wall at its upper end

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Engineering Mechanics
Two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are

15 N and 5 N

15 N and 15 N

20 N and 5 N

None of these

15 N and 5 N

15 N and 15 N

20 N and 5 N

None of these

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Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG + Ah2

IP = IG - Ah2

IP = Ah2 / IG

IP = IG / Ah2

IP = IG + Ah2

IP = IG - Ah2

IP = Ah2 / IG

IP = IG / Ah2

ANSWER DOWNLOAD EXAMIANS APP

Engineering Mechanics

Engineering Mechanics The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is

Engineering Mechanics The C.G. of a solid hemisphere lies on the central radius 3r

Engineering Mechanics A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act

Engineering Mechanics Two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are

Engineering Mechanics
The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is

Engineering Mechanics
The C.G. of a solid hemisphere lies on the central radius 3r

Engineering Mechanics
A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act

Engineering Mechanics
Two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are