According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG - Ah2

IP = Ah2 / IG

IP = IG + Ah2

IP = IG / Ah2

IP = IG - Ah2

IP = Ah2 / IG

IP = IG + Ah2

IP = IG / Ah2

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Engineering Mechanics
The centre of gravity of a right circular solid cone is at a distance of _________ from its base, measured along the vertical axis.(where h = Height of a right circular solid cone.)

h/4

h/2

h/6

h/3

h/4

h/2

h/6

h/3

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Engineering Mechanics
The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)

y = (gx²/2u² cos²α) + x. tanα

y = (gx²/2u² cos²α) - x. tanα

y = x. tanα + (gx²/2u² cos²α)

y = x. tanα - (gx²/2u² cos²α)

y = (gx²/2u² cos²α) + x. tanα

y = (gx²/2u² cos²α) - x. tanα

y = x. tanα + (gx²/2u² cos²α)

y = x. tanα - (gx²/2u² cos²α)

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Engineering Mechanics
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = Ah2 / IG

IP = IG / Ah2

IP = IG + Ah2

IP = IG - Ah2

IP = Ah2 / IG

IP = IG / Ah2

IP = IG + Ah2

IP = IG - Ah2

ANSWER DOWNLOAD EXAMIANS APP

Engineering Mechanics
Moment of inertia of a circular section about its diameter (d) is

πd4/32

πd3/16

πd3/32

πd4/64

πd4/32

πd3/16

πd3/32

πd4/64

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Engineering Mechanics
A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act

Upward at its upper end

Zero at its upper end

Downward at its upper end

Perpendicular to the wall at its upper end

Upward at its upper end

Zero at its upper end

Downward at its upper end

Perpendicular to the wall at its upper end

ANSWER DOWNLOAD EXAMIANS APP

Engineering Mechanics

Engineering Mechanics The centre of gravity of a right circular solid cone is at a distance of _________ from its base, measured along the vertical axis.(where h = Height of a right circular solid cone.)

Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)

Engineering Mechanics Moment of inertia of a circular section about its diameter (d) is

Engineering Mechanics A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act

Engineering Mechanics
The centre of gravity of a right circular solid cone is at a distance of _________ from its base, measured along the vertical axis.(where h = Height of a right circular solid cone.)

Engineering Mechanics
The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.)

Engineering Mechanics
Moment of inertia of a circular section about its diameter (d) is

Engineering Mechanics
A ladder is resting on a rough ground and leaning against a smooth vertical wall. The force of friction will act