Engineering Mechanics Centre of gravity of a solid cone lies on the axis at the height One third of the total height above base One-half of the total height above base One fourth of the total height above base Three eighth of the total height above the base One third of the total height above base One-half of the total height above base One fourth of the total height above base Three eighth of the total height above the base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Coplanar non-concurrent forces are those forces which __________ at one point, but their lines of action lie on the same plane. None of these Meet Do not meet Either ‘A’ or ‘B’ None of these Meet Do not meet Either ‘A’ or ‘B’ ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Non-coplanar concurrent forces are those forces which Meet at one point, but their lines of action do not lie on the same plane Do not meet at one point, but their lines of action lie on the same plane Meet at one point and their lines of action also lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane Meet at one point, but their lines of action do not lie on the same plane Do not meet at one point, but their lines of action lie on the same plane Meet at one point and their lines of action also lie on the same plane Do not meet at one point and their lines of action do not lie on the same plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is 30° 120° 90° 60° 30° 120° 90° 60° ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The law of the machine is (where P = Effort applied to lift the load, m = A constant which is equal to the slope of the line, W = Load lifted, and C = Another constant which represents the machine friction.) P = mW - C P = m/W + C P = C - mW P = mW + C P = mW - C P = m/W + C P = C - mW P = mW + C ANSWER DOWNLOAD EXAMIANS APP
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