Engineering Mechanics The moment of inertia of a solid sphere of mass ‘m’ and radius ‘r’ is mr² 2mr²/5 2mr²/3 mr²/2 mr² 2mr²/5 2mr²/3 mr²/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In a screw jack, the effort required to lift the load is given by (where W = Load lifted, α = Helix angle, and φ = Angle of friction.) P = W tan (α + φ) P = W tan (α - φ) P = W cos (α + φ) P = W tan (φ - α) P = W tan (α + φ) P = W tan (α - φ) P = W cos (α + φ) P = W tan (φ - α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The coefficient of restitution for inelastic bodies is One More than one Between zero and one Zero One More than one Between zero and one Zero ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum frictional force, which comes into play, when a body just begins to slide over the surface of the other body, is known as Limiting friction Dynamic friction Static friction Coefficient of friction Limiting friction Dynamic friction Static friction Coefficient of friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Mass moment of inertia of a uniform thin rod of mass M and length (l) about its mid-point and perpendicular to its length is (1/12) Ml² (2/3) Ml² (1/3) Ml² (3/4) Ml² (1/12) Ml² (2/3) Ml² (1/3) Ml² (3/4) Ml² ANSWER DOWNLOAD EXAMIANS APP
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