Engineering Mechanics The center of gravity of a semi-circle lies at a distance of __________ from its base measured along the vertical radius. 8r/3 3r/4π 3r/ 8 4r/ 3π 8r/3 3r/4π 3r/ 8 4r/ 3π ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The linear acceleration (a) of a body rotating along a circular path of radius (r) with an angular acceleration of α rad/s2, is a = r / α a = α.r None of these a = α/ r a = r / α a = α.r None of these a = α/ r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio of a first system of pulleys with 4 pulleys is 8 20 16 4 8 20 16 4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The unit of force in S.I. system of units is Watt Dyne Kilogram Newton Watt Dyne Kilogram Newton ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of gravity of an isosceles triangle with base (p) and sides (q) from its base is (p² - q²)/4 [√(4p² - q²)]/6 (p² + q²)/4 (4p² - q²)/6 (p² - q²)/4 [√(4p² - q²)]/6 (p² + q²)/4 (4p² - q²)/6 ANSWER DOWNLOAD EXAMIANS APP
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