Engineering Mechanics Moment of inertia is the All of these Second moment of force Second moment of area Second moment of mass All of these Second moment of force Second moment of area Second moment of mass ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum velocity of a particle moving with simple harmonic motion is ωr ω/r ω ω2r ωr ω/r ω ω2r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction in which the force acts. This statement is known as None of these Newton's first law of motion Newton's third law of motion Newton's second law of motion None of these Newton's first law of motion Newton's third law of motion Newton's second law of motion ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.) P = W tanα P = W tan (α + φ) P = W (cosα + μsinα) P = W (sinα + μcosα) P = W tanα P = W tan (α + φ) P = W (cosα + μsinα) P = W (sinα + μcosα) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
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