Engineering Mechanics The moment of inertia of a solid cone of mass ‘m’ and base radius ‘r’ about its vertical axis is 3mr²/10 4mr²/5 2mr²/5 3mr²/5 3mr²/10 4mr²/5 2mr²/5 3mr²/5 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The friction experienced by a body, when at rest, is known as Coefficient of friction Static friction Limiting friction Dynamic friction Coefficient of friction Static friction Limiting friction Dynamic friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Which of the following are vector quantities? All of these Linear velocity Linear acceleration Linear displacement All of these Linear velocity Linear acceleration Linear displacement ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum acceleration of a particle moving with simple harmonic motion is ω²r ω/r ω ωr ω²r ω/r ω ωr ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resolved part of the resultant of two forces inclined at an angle 'θ' in a given direction is equal to The algebraic sum of the resolved parts of the forces in the given direction The sum of the resolved parts of the forces in the given direction The difference of the forces multiplied by the cosine of θ The sum of the forces multiplied by the sine of θ The algebraic sum of the resolved parts of the forces in the given direction The sum of the resolved parts of the forces in the given direction The difference of the forces multiplied by the cosine of θ The sum of the forces multiplied by the sine of θ ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS