Engineering Mechanics The moment of inertia of a solid cone of mass ‘m’ and base radius ‘r’ about its vertical axis is 4mr²/5 2mr²/5 3mr²/5 3mr²/10 4mr²/5 2mr²/5 3mr²/5 3mr²/10 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will None of these Remain horizontal Slant up towards direction of pull Slant down towards direction of pull None of these Remain horizontal Slant up towards direction of pull Slant down towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to determine the effects of a force, acting on a body, we must know Line of action of the force Nature of the force i.e. whether the force is push or pull All of these Magnitude of the force Line of action of the force Nature of the force i.e. whether the force is push or pull All of these Magnitude of the force ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The friction experienced by a body, when at rest, is known as Dynamic friction Limiting friction Coefficient of friction Static friction Dynamic friction Limiting friction Coefficient of friction Static friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a circular section about an axis perpendicular to the section is πd3/32 πd4/64 πd4/32 πd3/16 πd3/32 πd4/64 πd4/32 πd3/16 ANSWER DOWNLOAD EXAMIANS APP
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