Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a circular section about its diameter (d) is πd4/32 πd3/16 πd4/64 πd3/32 πd4/32 πd3/16 πd4/64 πd3/32 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The power developed by a body acted upon by a torque 'T' Newton meter (N - m) and revolving at ω radian/s is given by T.ω/60 (in watts) T.ω/4500 (in kilowatts) T.ω (in watts) T.ω/75 (in kilowatts) T.ω/60 (in watts) T.ω/4500 (in kilowatts) T.ω (in watts) T.ω/75 (in kilowatts) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Center of gravity of a thin hollow cone lies on the axis at a height of One-third of the total height above base One-half of the total height above base Three-eighth of the total height above the base One-fourth of the total height above base One-third of the total height above base One-half of the total height above base Three-eighth of the total height above the base One-fourth of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The rate of doing work is known as None of these Power Potential energy Kinetic energy None of these Power Potential energy Kinetic energy ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is bh3/12 bh3/36 bh3/8 bh3/4 bh3/12 bh3/36 bh3/8 bh3/4 ANSWER DOWNLOAD EXAMIANS APP
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