Engineering Mechanics The maximum efficiency of a screw jack is (1 + tanφ)/(1 - tanφ) (1 - tanφ)/(1 + tanφ) (1 - sinφ)/(1 + sinφ) (1 + sinφ)/(1 - sinφ) (1 + tanφ)/(1 - tanφ) (1 - tanφ)/(1 + tanφ) (1 - sinφ)/(1 + sinφ) (1 + sinφ)/(1 - sinφ) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The periodic time of one oscillation for a simple pendulum is (where l = Length of the pendulum.) None of these (1/2π). √(l/g) (1/2π). √(g/l) 2π. √(l/g) None of these (1/2π). √(l/g) (1/2π). √(g/l) 2π. √(l/g) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum efficiency of a lifting machine is V.R./m 1/m m/V.R. 1/(m × V.R.) V.R./m 1/m m/V.R. 1/(m × V.R.) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics From a circular plate of diameter 6 cm is cut out a circle whose diameter is a radius of the plate. Find the e.g. of the remainder from the centre of circular plate 1.0 cm 1.5 cm 0.5 cm 2.5 cm 1.0 cm 1.5 cm 0.5 cm 2.5 cm ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Centre of gravity of a solid cone lies on the axis at the height One fourth of the total height above base Three eighth of the total height above the base One-half of the total height above base One third of the total height above base One fourth of the total height above base Three eighth of the total height above the base One-half of the total height above base One third of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P + m.a = 0 P × m.a = 0 P/m.a = 0 P - m.a = 0 P + m.a = 0 P × m.a = 0 P/m.a = 0 P - m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
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