Engineering Mechanics The maximum efficiency of a screw jack is (1 - tanφ)/(1 + tanφ) (1 - sinφ)/(1 + sinφ) (1 + sinφ)/(1 - sinφ) (1 + tanφ)/(1 - tanφ) (1 - tanφ)/(1 + tanφ) (1 - sinφ)/(1 + sinφ) (1 + sinφ)/(1 - sinφ) (1 + tanφ)/(1 - tanφ) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P - m.a = 0 P/m.a = 0 P × m.a = 0 P + m.a = 0 P - m.a = 0 P/m.a = 0 P × m.a = 0 P + m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In actual machines, mechanical advantage is _________ velocity ratio. None of these Equal to Greater than Less than None of these Equal to Greater than Less than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum efficiency of a lifting machine is m/V.R. 1/m V.R./m 1/(m × V.R.) m/V.R. 1/m V.R./m 1/(m × V.R.) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In a screw jack, the effort required to lift the load is given by (where W = Load lifted, α = Helix angle, and φ = Angle of friction.) P = W tan (α - φ) P = W tan (α + φ) P = W cos (α + φ) P = W tan (φ - α) P = W tan (α - φ) P = W tan (α + φ) P = W cos (α + φ) P = W tan (φ - α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia is the Second moment of mass Second moment of force Second moment of area All of these Second moment of mass Second moment of force Second moment of area All of these ANSWER DOWNLOAD EXAMIANS APP
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