Engineering Mechanics The potential energy of a vertically raised body is __________ the kinetic energy of a vertically falling body. Less than Greater than None of these Equal to Less than Greater than None of these Equal to ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The skidding away of the vehicle on a level circular path can be avoided if the force of friction between the wheels and the ground is __________ the centrifugal force. None of these Greater than Equal to Less than None of these Greater than Equal to Less than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics One joule means that Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 kg when it displaces a body through 1 m Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 kg when it displaces a body through 1 m Work is done by a force of 1 g when it displaces a body through 1 cm ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the balls with velocity ‘v’ is made to strike the second ball. Both the balls after impact will move with a velocity v/2 v/4 v/8 v v/2 v/4 v/8 v ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Remain horizontal None of these Slant up towards direction of pull Slant down towards direction of pull Remain horizontal None of these Slant up towards direction of pull Slant down towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
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