Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is bh3/36 bh3/8 bh3/12 bh3/4 bh3/36 bh3/8 bh3/12 bh3/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Three forces acting on a rigid body are represented in magnitude, direction and line of action by the three sides of a triangle taken in order. The forces are equivalent to a couple whose moment is equal to None of these Twice the area of the triangle Half the area of the triangle Area of the triangle None of these Twice the area of the triangle Half the area of the triangle Area of the triangle ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces which do not meet at one point and their lines of action do not lie on the same plane are known as Non-coplanar concurrent forces None of these Coplanar concurrent forces Coplanar non-concurrent forces Non-coplanar concurrent forces None of these Coplanar concurrent forces Coplanar non-concurrent forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The time of flight (t) of a projectile on a horizontal plane is given by t = 2u. cosα/g t = 2u. sinα/g t = 2u/g.sinα t = 2u. tanα/g t = 2u. cosα/g t = 2u. sinα/g t = 2u/g.sinα t = 2u. tanα/g ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is bh3/12 bh3/36 bh3/4 bh3/8 bh3/12 bh3/36 bh3/4 bh3/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If a number of forces are acting at a point, their resultant will be inclined at an angle 'θ' with the horizontal, such that tanθ = ΣV × ΣH tanθ = ΣH/ΣV tanθ = ΣV/ΣH tanθ = √(ΣV + ΣH) tanθ = ΣV × ΣH tanθ = ΣH/ΣV tanθ = ΣV/ΣH tanθ = √(ΣV + ΣH) ANSWER DOWNLOAD EXAMIANS APP
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