Engineering Mechanics The range of projectile will be maximum for a given velocity of projectile, when the angle of projection (α) is 45° + β/2 30° + β/2 60° + β/2 β/2 45° + β/2 30° + β/2 60° + β/2 β/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity of a body on reaching the ground from a height h, is 2.√(gh) 2g.√h √(2gh) √(gh) 2.√(gh) 2g.√h √(2gh) √(gh) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A block of mass 20 kg lying on a rough horizontal plane is connected by a light string passing over a smooth pulley to another mass 5 kg, which can move freely in the Vertical direction, as shown in the below figure. The tension in the string will ___________ with the increase in coefficient of friction. Decrease Not be effected Increase None of these Decrease Not be effected Increase None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The periodic time of a particle with simple harmonic motion is _________ proportional to the angular velocity. Inversely None of these Square root Directly Inversely None of these Square root Directly ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The principle of transmissibility of forces states that, when a force acts upon a body, its effect is Maximum, if it acts at the center of gravity of the body Different at different points on its line of action Same at every point on its line of action Minimum, if it acts at the center of gravity of the body Maximum, if it acts at the center of gravity of the body Different at different points on its line of action Same at every point on its line of action Minimum, if it acts at the center of gravity of the body ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
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