Engineering Mechanics The range of projectile will be maximum for a given velocity of projectile, when the angle of projection (α) is 45° + β/2 60° + β/2 β/2 30° + β/2 45° + β/2 60° + β/2 β/2 30° + β/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is 2v v 4v 8v 2v v 4v 8v ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Centre of gravity of a solid cone lies on the axis at the height Three eighth of the total height above the base One-half of the total height above base One third of the total height above base One fourth of the total height above base Three eighth of the total height above the base One-half of the total height above base One third of the total height above base One fourth of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Which of the following is an equation of linear motion?(where, u and v = Initial and final velocity of the body, a = Acceleration of the body, and s = Displacement of the body in time t seconds.) s = u.t + ½ a.t2 v2 = u2 + 2a.s v = u + a.t All of these s = u.t + ½ a.t2 v2 = u2 + 2a.s v = u + a.t All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If rain is falling in the opposite direction of the movement of a pedestrian, he has to hold his umbrella Less inclined when standing More inclined when moving Less inclined when moving More inclined when standing Less inclined when standing More inclined when moving Less inclined when moving More inclined when standing ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
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