Engineering Mechanics The range of projectile will be maximum for a given velocity of projectile, when the angle of projection (α) is β/2 60° + β/2 45° + β/2 30° + β/2 β/2 60° + β/2 45° + β/2 30° + β/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If u₁ and u₂ are the velocities of two moving bodies in the same direction before impact and v₁ and v₂ are their velocities after impact, then coefficient of restitution is given by (u₂ + u₁)/(v₂ + v₁) (v₂ - v₁)/(u₁ - u₂) (v₁ - v₂)/(u₁ - u₂) (u₁ - u₂)/(v₁ - v₂) (u₂ + u₁)/(v₂ + v₁) (v₂ - v₁)/(u₁ - u₂) (v₁ - v₂)/(u₁ - u₂) (u₁ - u₂)/(v₁ - v₂) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A smooth cylinder lying on its convex surface remains in __________ equilibrium. Unstable None of these Stable Neutral Unstable None of these Stable Neutral ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a square of side (a) about an axis through its center of gravity is a4/36 a4/4 a4/12 a4/8 a4/36 a4/4 a4/12 a4/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of percussion of the homogeneous rod of length ‘L’ suspended at the top will be 3L/4 L/2 2L/3 L/3 3L/4 L/2 2L/3 L/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
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