Engineering Mechanics In order to completely specify angular displacement by a vector, it must fix Direction of the axis of rotation Magnitude of angular displacement All of these Sense of angular displacement Direction of the axis of rotation Magnitude of angular displacement All of these Sense of angular displacement ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Work done is said to be zero, when No force acts on a body but some displacement takes place None of these Some force acts on a body, but displacement is zero Either (A) or (B) No force acts on a body but some displacement takes place None of these Some force acts on a body, but displacement is zero Either (A) or (B) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Slant down towards direction of pull None of these Remain horizontal Slant up towards direction of pull Slant down towards direction of pull None of these Remain horizontal Slant up towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Center of gravity of a thin hollow cone lies on the axis at a height of One-fourth of the total height above base One-third of the total height above base Three-eighth of the total height above the base One-half of the total height above base One-fourth of the total height above base One-third of the total height above base Three-eighth of the total height above the base One-half of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The potential energy of a vertically raised body is __________ the kinetic energy of a vertically falling body. None of these Equal to Less than Greater than None of these Equal to Less than Greater than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of the two forces ‘P’ and ‘Q’ is ‘R’. If ‘Q’ is doubled, the new resultant is perpendicular to ‘P’. Then None of the listed here Q = 2R Q = R P = Q None of the listed here Q = 2R Q = R P = Q ANSWER DOWNLOAD EXAMIANS APP
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