Engineering Mechanics The maximum height of a projectile on a horizontal plane, is u² cos²α/g u² sin²α/2g u² cos²α/2g u² sin²α/g u² cos²α/g u² sin²α/2g u² cos²α/2g u² sin²α/g ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is 4v 2v 8v v 4v 2v 8v v ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When two elastic bodies collide with each other, The two bodies begin to regain their original shape The two bodies tend to compress and deform at the surface of contact The two bodies will momentarily come to rest after collision All of these The two bodies begin to regain their original shape The two bodies tend to compress and deform at the surface of contact The two bodies will momentarily come to rest after collision All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of percussion is below the centre of gravity of the body and is at a distance equal to kG2/h h × kG h2/kG h/kG kG2/h h × kG h2/kG h/kG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
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