Engineering Mechanics In a screw jack, the effort required to lower the load is __________ the effort required to raise the same load. Less than None of these Equal to More than Less than None of these Equal to More than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The ideal angle of banking provided on the curves on roads depends upon Nature of the road surface Weight of the vehicle Coefficient of friction between the road and vehicle contact point (Velocity)2 of the vehicle Nature of the road surface Weight of the vehicle Coefficient of friction between the road and vehicle contact point (Velocity)2 of the vehicle ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Centre of gravity of a solid cone lies on the axis at the height Three eighth of the total height above the base One fourth of the total height above base One third of the total height above base One-half of the total height above base Three eighth of the total height above the base One fourth of the total height above base One third of the total height above base One-half of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A particle moves along a straight line such that distance (x) traversed in 't' seconds is given by x = t² (t - 4), the acceleration of the particle will be given by the equation 6f - 4 6t² - 8t 6f - 8 3t² + 2t 6f - 4 6t² - 8t 6f - 8 3t² + 2t ANSWER DOWNLOAD EXAMIANS APP
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